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Oud 8 juni 2017, 23:18   #19
Nr.10
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  • FLOP = FLoating-point OPeration
  • FLOPs = FLoating-point OPerations
  • FLOPS = FLoating point OPerations per second
Citaat:
GFLOPS = #chassis * #nodes/chassis * #sockets/node * #cores/socket * GHz/core * FLOPs/cycle
In general, a core can do a certain number of FLOPs or FLoating-point OPerations every time its internal clock ticks. These clock ticks are called cycles and measured in Hertz (Hz). Most microprocessors today can do four (4) FLOPs per clock cycle, that is, 4 FLOPs per Hz. Thus, depending upon the Hz frequency of the processor’s internal clock, the floating point operations per second or FLOPS can be calculated. The internal clock speed of the core is known. It’s that GHz rating typical of today’s processor. For example, a 2.5-GHz processor ticks 2.5 billion times per second (Giga ~ billion). Therefore, a 2.5-GHz processor ticking 2.5 billion times per second and capable of performing 4 FLOPs each tick is rated with a theoretical performance of 10 billion FLOPs per second or 10 GFLOPS.
Citaat:
The internal clock speed of the core is known. It’s that GHz rating typical of today’s processor.
  • kFLOPS = kilo = 10 tot de 3de macht
  • MFLPS = mega = 10 ^ 6
  • GFLOPS = giga = 10 ^ 9
  • TFLOPS = tera = 10 ^ 12
  • PFLOPS = peta = 10 ^ 15
  • EFLOPS = exa = 10 ^ 18
Bijvoorbeeld: een desktop met
  • 1 socket
  • 1 core
  • een interne kloksnelheid van 2,5 Ghz
  • 4 FLOPs per klok-cyclus
==> levert een capaciteit van 10 GFLOPS = 10 miljard FLOPs per seconde
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Laatst gewijzigd door Nr.10 : 8 juni 2017 om 23:33.
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